Using flag diacritics for faster compilation
From LING073
lexd is a bit slow to compile dictionaries that make heavy use of filters.
To speed this up, you can enable compiling to flag diacritics.
Contents
Implementing the change
First thing you want to do is edit your Makefile.am:
- remove
autogen.binandautomorf.binlines from theTARGETS_COMMONlist at the top - add
-fas a switch to thelexdcommmands - add
-Fas a switch to thehfst-composecommand in the theautomorf.hfstline
This will all look something like this:
TARGETS_COMMON = \
$(LANG1).automorf.hfst \
- $(LANG1).automorf.bin \
$(LANG1).automorf.att.gz \
$(LANG1).autogen.hfst \
- $(LANG1).autogen.bin \
$(LANG1).autogen.att.gz \
$(LANG1).autopgen.bin \
$(LANG1).rlx.bin \
$(LANG1).zhfst
.deps/$(LANG1).RL.lexd.hfst: .deps/$(LANG1).RL.lexd
- lexd $< .deps/$(LANG1).RL.lexd.att
+ lexd -f $< .deps/$(LANG1).RL.lexd.att
hfst-txt2fst .deps/$(LANG1).RL.lexd.att -o $@
.deps/$(LANG1).LR.lexd.hfst: .deps/$(LANG1).LR.lexd
- lexd $< .deps/$(LANG1).LR.lexd.att
+ lexd -f $< .deps/$(LANG1).LR.lexd.att
hfst-txt2fst .deps/$(LANG1).LR.lexd.att -o $@
$(LANG1).automorf.hfst: .deps/$(LANG1).LR.hfst .deps/$(LANG1).spellrelax.hfst - hfst-compose -1 $< -2 .deps/$(LANG1).spellrelax.hfst | hfst-invert | hfst-fst2fst -O -o $@ + hfst-compose -F -1 $< -2 .deps/$(LANG1).spellrelax.hfst | hfst-invert | hfst-fst2fst -O -o $@
Additional steps
Updating modes.xml
You'll want to change all the instances of lt-proc and auto*.bin in your modes.xml file to hfst-proc and auto*.hfst, respectively.
Running hfst-expand and hfst-lookup
You'll also need to add -X obey-flags to hfst-expand or hfst-lookup.
Running tests
In theory you shouldn't have to do anything extra?